4y^5+12y^4-40y^3=f(y)

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Solution for 4y^5+12y^4-40y^3=f(y) equation: 


Simplifying
4y5 + 12y4 + -40y3 = f(y)

Reorder the terms:
-40y3 + 12y4 + 4y5 = f(y)

Multiply f * y
-40y3 + 12y4 + 4y5 = fy

Solving
-40y3 + 12y4 + 4y5 = fy

Solving for variable 'y'.

Reorder the terms:
-1fy + -40y3 + 12y4 + 4y5 = fy + -1fy

Combine like terms: fy + -1fy = 0
-1fy + -40y3 + 12y4 + 4y5 = 0

Factor out the Greatest Common Factor (GCF), 'y'.
y(-1f + -40y2 + 12y3 + 4y4) = 0


Subproblem 1
Set the factor 'y' equal to zero and attempt to solve:

Simplifying
y = 0

Solving
y = 0

Move all terms containing y to the left, all other terms to the right.

Simplifying
y = 0

Subproblem 2
Set the factor '(-1f + -40y2 + 12y3 + 4y4)' equal to zero and attempt to solve:

Simplifying
-1f + -40y2 + 12y3 + 4y4 = 0

Solving
-1f + -40y2 + 12y3 + 4y4 = 0

The solution to this equation could not be determined.

This subproblem is being ignored because a solution could not be determined.
Solution
y = {0}

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